Identify the element with the electron configuration [Kr] 5s² 4d¹⁰ 5p⁴.

The given electron configuration is [Kr] 5s² 4d¹⁰ 5p⁴. This indicates that the element has a total of 34 electrons beyond the noble gas configuration of krypton (Kr), which accounts for 36 electrons. In the given configuration, the two electrons in the 5s subshell, the ten in the 4d subshell, and the four in the 5p subshell total up to 16 additional electrons. When combined with the 36 from krypton, this gives us 52 electrons in total.

The element with atomic number 52 is tellurium (Te). It belongs to group 16 of the periodic table, which is also known as the chalcogens. The presence of two electrons in the 5s subshell and a complete 4d subshell (10 electrons), along with four electrons in the 5p, aligns perfectly with the electron configuration of tellurium.

The other elements listed do not match this electron configuration based on their atomic numbers or the arrangement of electrons in the specified subshells.