What is the chemical symbol for the element with the configuration [Xe] 6s² 4f¹¹?

The electron configuration [Xe] 6s² 4f¹¹ corresponds to the element that has a total of 58 electrons in its outer shell, specifically in the 4f and 6s subshells. The notation indicates that the element has the same electron configuration as xenon up to the noble gas core, followed by two electrons in the 6s subshell and eleven electrons in the 4f subshell.

This configuration points to an element in the lanthanide series, which includes the f-block elements where the 4f subshell is being filled. When analyzing the number of 4f electrons, we find that all relevant elements leading up to element 71 (lutetium) are indeed in the f-block. Since the configuration specifies 4f¹¹, this directly identifies the element as having the atomic number of 67.

Holmium (Ho) is the element with atomic number 67, making it the correct corresponding symbol for this configuration. The presence of the filled 4f subshell contributes significantly to the chemical properties of the element, which include its magnetic and optical characteristics. Hence, the chemical symbol for the element with the configuration [Xe] 6s² 4f